Having conquered Delhi in their own backyard, a high on confidence Sunrisers Hyderabad will now take on Mumbai Indians in the second header in IPL 2019 on Saturday at the Rajiv Gandhi International Stadium. Mumbai too will be wearing a confident look after beating defending champions Chennai Super Kings in their last encounter.
It will indeed be a battle of equals when both teams look to carry their winning momentum forward. While SRH have looked the most balanced unit in the competition so far, everyone knows that MI can turn any game upside down on their day. It will come down to both teams looking to do the basics right.
When it comes to the bowling, SRH have one of the best attacks in the tournament. While stand-in skipper Bhuvneshwar Kumar returning to form against Delhi Capitals on Thursday was a welcome sight, Rashid Khan and Mohammad Nabi have already shown what they are capable of on Indian tracks which have all taken turn. With the Uppal wicket likely to be a sporting one, it will definitely be a battle of equals on Saturday as SRH and MI both look to bag two points from the game.
SUNRISERS HYDERABAD: David Warner, Jonny Bairstow (wk), Vijay Shankar, Manish Pandey, Deepak Hooda, Yusuf Pathan, Mohammad Nabi, Rashid Khan, Bhuvneshwar Kumar, Sandeep Sharma, Siddarth Kaul.
MUMBAI INDIANS: Rohit Sharma (c), Quinton de Kock (wk), Suryakumar Yadav, Ishan Kishan, Kieron Pollard, Krunal Pandya, Hardik Pandya, Mayank Markande, Jasprit Bumrah, Jason Behrendorff, Mitchell McClenaghan.
FPJ’s dream 11: David Warner, Jonny Bairstow, Vijay Shankar, Rohit Sharma, Hardik Pandya, Suryakumar Yadav, Jason Behrendorff, Jasprit Bumrah, Bhuvneshwar Kumar, Krunal Pandya, Yusuf Pathan.
With agency inputs