Having won their last three games at home, Kings XI Punjab will now head to the iconic Wankhede Stadium to take on Mumbai Indians in what is expected to be a mouth-watering clash in IPL 2019. Both teams have defeated Sunrisers Hyderabad in their last games. While MI thrashed SRH by 40 runs, KXIP won by six wickets.
Playing at home, it will obviously be an added advantage for Mumbai as they know the ground conditions well. But the boys need to fire in unison against a quality KXIP outfit and skipper Rohit Sharma will look to lead by example. Having failed to put on a quality show so far in this edition of the cash-rich league, Rohit would be looking to use this opportunity to strike some form.
For Punjab, it has been a slowish sort of display from the batsman. While it cannot be denied that they have played their last two games on conditions that weren’t best for batting — in Chennai and Mohali — the wicket in Wankhede should aide stroke play and considering the form that the likes of K.L. Rahul and Mayank Agarwal are in, they would be waiting to put on their pads and take strike. All in all, it should be a good contest between two quality units looking to keep the winning momentum going.
Expected playing 11
Mumbai Indians: Rohit Sharma, Quinton de Kock, Suryakumar Yadav, Krunal Pandya, Mayank Markande, Barinder Sran, Kieron Pollard, Hardik Pandya, Jasprit Bumrah, Mitchell McClenaghan, Alzarri Joseph.
Kings XI Punjab: Chris Gayle, Lokesh Rahul, Mayank Agarwal, Sarfaraz Khan, Sam Curran, Ravichandran Ashwin, Mohammed Shami, Mujeeb Ur Rahman, Ankit Rajpoot, David Miller, Mandeep Singh.
FPJ’s dream 11: Rohit Sharma, Quinton de Kock, Kieron Pollard, Hardik Pandya, Lokesh Rahul, Mayank Agarwal, Sarfaraz Khan, Mohammed Shami, Ravichandran Ashwin, Alzarri Joseph, Jasprit Bumrah.
With IANS inputs